Optimal. Leaf size=250 \[ -\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b d \left (a^2+b^2\right ) \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 d \left (a^2+b^2\right )}-\frac{3 a \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{b^{5/2} d}+\frac{i \tan ^{-1}\left (\frac{\sqrt{-b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d (-b+i a)^{3/2}}+\frac{i \tanh ^{-1}\left (\frac{\sqrt{b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d (b+i a)^{3/2}} \]
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Rubi [A] time = 1.54963, antiderivative size = 250, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 10, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.4, Rules used = {3565, 3647, 3655, 6725, 63, 217, 206, 93, 205, 208} \[ -\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b d \left (a^2+b^2\right ) \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 d \left (a^2+b^2\right )}-\frac{3 a \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{b^{5/2} d}+\frac{i \tan ^{-1}\left (\frac{\sqrt{-b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d (-b+i a)^{3/2}}+\frac{i \tanh ^{-1}\left (\frac{\sqrt{b+i a} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{d (b+i a)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3565
Rule 3647
Rule 3655
Rule 6725
Rule 63
Rule 217
Rule 206
Rule 93
Rule 205
Rule 208
Rubi steps
\begin{align*} \int \frac{\tan ^{\frac{7}{2}}(c+d x)}{(a+b \tan (c+d x))^{3/2}} \, dx &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{2 \int \frac{\sqrt{\tan (c+d x)} \left (\frac{3 a^2}{2}-\frac{1}{2} a b \tan (c+d x)+\frac{1}{2} \left (3 a^2+b^2\right ) \tan ^2(c+d x)\right )}{\sqrt{a+b \tan (c+d x)}} \, dx}{b \left (a^2+b^2\right )}\\ &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}+\frac{2 \int \frac{-\frac{1}{4} a \left (3 a^2+b^2\right )-\frac{1}{2} b^3 \tan (c+d x)-\frac{3}{4} a \left (a^2+b^2\right ) \tan ^2(c+d x)}{\sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}} \, dx}{b^2 \left (a^2+b^2\right )}\\ &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}+\frac{2 \operatorname{Subst}\left (\int \frac{-\frac{1}{4} a \left (3 a^2+b^2\right )-\frac{b^3 x}{2}-\frac{3}{4} a \left (a^2+b^2\right ) x^2}{\sqrt{x} \sqrt{a+b x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{b^2 \left (a^2+b^2\right ) d}\\ &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}+\frac{2 \operatorname{Subst}\left (\int \left (-\frac{3 a \left (a^2+b^2\right )}{4 \sqrt{x} \sqrt{a+b x}}+\frac{a b^2-b^3 x}{2 \sqrt{x} \sqrt{a+b x} \left (1+x^2\right )}\right ) \, dx,x,\tan (c+d x)\right )}{b^2 \left (a^2+b^2\right ) d}\\ &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}-\frac{(3 a) \operatorname{Subst}\left (\int \frac{1}{\sqrt{x} \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 b^2 d}+\frac{\operatorname{Subst}\left (\int \frac{a b^2-b^3 x}{\sqrt{x} \sqrt{a+b x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{b^2 \left (a^2+b^2\right ) d}\\ &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}-\frac{(3 a) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^2}} \, dx,x,\sqrt{\tan (c+d x)}\right )}{b^2 d}+\frac{\operatorname{Subst}\left (\int \left (\frac{i a b^2+b^3}{2 (i-x) \sqrt{x} \sqrt{a+b x}}+\frac{i a b^2-b^3}{2 \sqrt{x} (i+x) \sqrt{a+b x}}\right ) \, dx,x,\tan (c+d x)\right )}{b^2 \left (a^2+b^2\right ) d}\\ &=-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}-\frac{\operatorname{Subst}\left (\int \frac{1}{(i-x) \sqrt{x} \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 (i a-b) d}-\frac{(3 a) \operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{b^2 d}-\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{x} (i+x) \sqrt{a+b x}} \, dx,x,\tan (c+d x)\right )}{2 (i a+b) d}\\ &=-\frac{3 a \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{b^{5/2} d}-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}-\frac{\operatorname{Subst}\left (\int \frac{1}{i-(a+i b) x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{(i a-b) d}-\frac{\operatorname{Subst}\left (\int \frac{1}{i-(-a+i b) x^2} \, dx,x,\frac{\sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{(i a+b) d}\\ &=\frac{i \tan ^{-1}\left (\frac{\sqrt{i a-b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{(i a-b)^{3/2} d}-\frac{3 a \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{b^{5/2} d}+\frac{i \tanh ^{-1}\left (\frac{\sqrt{i a+b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{(i a+b)^{3/2} d}-\frac{2 a^2 \tan ^{\frac{3}{2}}(c+d x)}{b \left (a^2+b^2\right ) d \sqrt{a+b \tan (c+d x)}}+\frac{\left (3 a^2+b^2\right ) \sqrt{\tan (c+d x)} \sqrt{a+b \tan (c+d x)}}{b^2 \left (a^2+b^2\right ) d}\\ \end{align*}
Mathematica [C] time = 2.97278, size = 270, normalized size = 1.08 \[ \frac{\frac{2 \tan ^{\frac{5}{2}}(c+d x) \sqrt{\frac{b \tan (c+d x)}{a}+1} \, _2F_1\left (\frac{3}{2},\frac{5}{2};\frac{7}{2};-\frac{b \tan (c+d x)}{a}\right )}{a \sqrt{a+b \tan (c+d x)}}-\frac{5 \sqrt{\tan (c+d x)}}{(a-i b) \sqrt{a+b \tan (c+d x)}}-\frac{5 \sqrt{\tan (c+d x)}}{(a+i b) \sqrt{a+b \tan (c+d x)}}+\frac{5 (-1)^{3/4} \tanh ^{-1}\left (\frac{\sqrt [4]{-1} \sqrt{-a-i b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{(-a-i b)^{3/2}}-\frac{5 (-1)^{3/4} \tanh ^{-1}\left (\frac{\sqrt [4]{-1} \sqrt{a-i b} \sqrt{\tan (c+d x)}}{\sqrt{a+b \tan (c+d x)}}\right )}{(a-i b)^{3/2}}}{5 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.713, size = 763794, normalized size = 3055.2 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan \left (d x + c\right )^{\frac{7}{2}}}{{\left (b \tan \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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